Integrand size = 27, antiderivative size = 194 \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {3}{128} b \left (8 a^2+b^2\right ) x-\frac {a \left (2 a^2+61 b^2\right ) \cos ^5(c+d x)}{560 d}+\frac {3 b \left (8 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{128 d}+\frac {b \left (8 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{64 d}-\frac {\left (2 a^2+7 b^2\right ) \cos ^5(c+d x) (a+b \sin (c+d x))}{112 d}-\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d}-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d} \]
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Time = 0.24 (sec) , antiderivative size = 194, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {2941, 2748, 2715, 8} \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=-\frac {a \left (2 a^2+61 b^2\right ) \cos ^5(c+d x)}{560 d}-\frac {\left (2 a^2+7 b^2\right ) \cos ^5(c+d x) (a+b \sin (c+d x))}{112 d}+\frac {b \left (8 a^2+b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{64 d}+\frac {3 b \left (8 a^2+b^2\right ) \sin (c+d x) \cos (c+d x)}{128 d}+\frac {3}{128} b x \left (8 a^2+b^2\right )-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d}-\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d} \]
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Rule 8
Rule 2715
Rule 2748
Rule 2941
Rubi steps \begin{align*} \text {integral}& = -\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d}+\frac {1}{8} \int \cos ^4(c+d x) (3 b+3 a \sin (c+d x)) (a+b \sin (c+d x))^2 \, dx \\ & = -\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d}-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d}+\frac {1}{56} \int \cos ^4(c+d x) (a+b \sin (c+d x)) \left (27 a b+3 \left (2 a^2+7 b^2\right ) \sin (c+d x)\right ) \, dx \\ & = -\frac {\left (2 a^2+7 b^2\right ) \cos ^5(c+d x) (a+b \sin (c+d x))}{112 d}-\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d}-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d}+\frac {1}{336} \int \cos ^4(c+d x) \left (21 b \left (8 a^2+b^2\right )+3 a \left (2 a^2+61 b^2\right ) \sin (c+d x)\right ) \, dx \\ & = -\frac {a \left (2 a^2+61 b^2\right ) \cos ^5(c+d x)}{560 d}-\frac {\left (2 a^2+7 b^2\right ) \cos ^5(c+d x) (a+b \sin (c+d x))}{112 d}-\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d}-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d}+\frac {1}{16} \left (b \left (8 a^2+b^2\right )\right ) \int \cos ^4(c+d x) \, dx \\ & = -\frac {a \left (2 a^2+61 b^2\right ) \cos ^5(c+d x)}{560 d}+\frac {b \left (8 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{64 d}-\frac {\left (2 a^2+7 b^2\right ) \cos ^5(c+d x) (a+b \sin (c+d x))}{112 d}-\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d}-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d}+\frac {1}{64} \left (3 b \left (8 a^2+b^2\right )\right ) \int \cos ^2(c+d x) \, dx \\ & = -\frac {a \left (2 a^2+61 b^2\right ) \cos ^5(c+d x)}{560 d}+\frac {3 b \left (8 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{128 d}+\frac {b \left (8 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{64 d}-\frac {\left (2 a^2+7 b^2\right ) \cos ^5(c+d x) (a+b \sin (c+d x))}{112 d}-\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d}-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d}+\frac {1}{128} \left (3 b \left (8 a^2+b^2\right )\right ) \int 1 \, dx \\ & = \frac {3}{128} b \left (8 a^2+b^2\right ) x-\frac {a \left (2 a^2+61 b^2\right ) \cos ^5(c+d x)}{560 d}+\frac {3 b \left (8 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{128 d}+\frac {b \left (8 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{64 d}-\frac {\left (2 a^2+7 b^2\right ) \cos ^5(c+d x) (a+b \sin (c+d x))}{112 d}-\frac {3 a \cos ^5(c+d x) (a+b \sin (c+d x))^2}{56 d}-\frac {\cos ^5(c+d x) (a+b \sin (c+d x))^3}{8 d} \\ \end{align*}
Time = 0.53 (sec) , antiderivative size = 189, normalized size of antiderivative = 0.97 \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {3360 a^2 b c+840 b^3 c+3360 a^2 b d x+420 b^3 d x-280 a \left (8 a^2+9 b^2\right ) \cos (c+d x)-280 \left (4 a^3+3 a b^2\right ) \cos (3 (c+d x))-224 a^3 \cos (5 (c+d x))+168 a b^2 \cos (5 (c+d x))+120 a b^2 \cos (7 (c+d x))+840 a^2 b \sin (2 (c+d x))-840 a^2 b \sin (4 (c+d x))-140 b^3 \sin (4 (c+d x))-280 a^2 b \sin (6 (c+d x))+\frac {35}{2} b^3 \sin (8 (c+d x))}{17920 d} \]
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Time = 0.84 (sec) , antiderivative size = 177, normalized size of antiderivative = 0.91
method | result | size |
parallelrisch | \(\frac {\left (-2240 a^{3}-1680 a \,b^{2}\right ) \cos \left (3 d x +3 c \right )+\left (-448 a^{3}+336 a \,b^{2}\right ) \cos \left (5 d x +5 c \right )+\left (-1680 a^{2} b -280 b^{3}\right ) \sin \left (4 d x +4 c \right )+240 a \,b^{2} \cos \left (7 d x +7 c \right )+1680 a^{2} b \sin \left (2 d x +2 c \right )-560 a^{2} b \sin \left (6 d x +6 c \right )+35 b^{3} \sin \left (8 d x +8 c \right )+\left (-4480 a^{3}-5040 a \,b^{2}\right ) \cos \left (d x +c \right )+6720 a^{2} b d x +840 b^{3} d x -7168 a^{3}-6144 a \,b^{2}}{35840 d}\) | \(177\) |
derivativedivides | \(\frac {-\frac {a^{3} \left (\cos ^{5}\left (d x +c \right )\right )}{5}+3 a^{2} b \left (-\frac {\sin \left (d x +c \right ) \left (\cos ^{5}\left (d x +c \right )\right )}{6}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{24}+\frac {d x}{16}+\frac {c}{16}\right )+3 a \,b^{2} \left (-\frac {\left (\sin ^{2}\left (d x +c \right )\right ) \left (\cos ^{5}\left (d x +c \right )\right )}{7}-\frac {2 \left (\cos ^{5}\left (d x +c \right )\right )}{35}\right )+b^{3} \left (-\frac {\left (\sin ^{3}\left (d x +c \right )\right ) \left (\cos ^{5}\left (d x +c \right )\right )}{8}-\frac {\sin \left (d x +c \right ) \left (\cos ^{5}\left (d x +c \right )\right )}{16}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{64}+\frac {3 d x}{128}+\frac {3 c}{128}\right )}{d}\) | \(180\) |
default | \(\frac {-\frac {a^{3} \left (\cos ^{5}\left (d x +c \right )\right )}{5}+3 a^{2} b \left (-\frac {\sin \left (d x +c \right ) \left (\cos ^{5}\left (d x +c \right )\right )}{6}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{24}+\frac {d x}{16}+\frac {c}{16}\right )+3 a \,b^{2} \left (-\frac {\left (\sin ^{2}\left (d x +c \right )\right ) \left (\cos ^{5}\left (d x +c \right )\right )}{7}-\frac {2 \left (\cos ^{5}\left (d x +c \right )\right )}{35}\right )+b^{3} \left (-\frac {\left (\sin ^{3}\left (d x +c \right )\right ) \left (\cos ^{5}\left (d x +c \right )\right )}{8}-\frac {\sin \left (d x +c \right ) \left (\cos ^{5}\left (d x +c \right )\right )}{16}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{64}+\frac {3 d x}{128}+\frac {3 c}{128}\right )}{d}\) | \(180\) |
risch | \(\frac {3 a^{2} b x}{16}+\frac {3 b^{3} x}{128}-\frac {a^{3} \cos \left (d x +c \right )}{8 d}-\frac {9 a \,b^{2} \cos \left (d x +c \right )}{64 d}+\frac {b^{3} \sin \left (8 d x +8 c \right )}{1024 d}+\frac {3 a \,b^{2} \cos \left (7 d x +7 c \right )}{448 d}-\frac {a^{2} b \sin \left (6 d x +6 c \right )}{64 d}-\frac {a^{3} \cos \left (5 d x +5 c \right )}{80 d}+\frac {3 \cos \left (5 d x +5 c \right ) a \,b^{2}}{320 d}-\frac {3 b \sin \left (4 d x +4 c \right ) a^{2}}{64 d}-\frac {b^{3} \sin \left (4 d x +4 c \right )}{128 d}-\frac {a^{3} \cos \left (3 d x +3 c \right )}{16 d}-\frac {3 \cos \left (3 d x +3 c \right ) a \,b^{2}}{64 d}+\frac {3 a^{2} b \sin \left (2 d x +2 c \right )}{64 d}\) | \(220\) |
norman | \(\frac {-\frac {b \left (248 a^{2}+671 b^{2}\right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}+\frac {b \left (248 a^{2}+671 b^{2}\right ) \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}-\frac {b \left (104 a^{2}+333 b^{2}\right ) \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}-\frac {b \left (328 a^{2}-23 b^{2}\right ) \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}+\frac {3 b \left (8 a^{2}+b^{2}\right ) \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}+\frac {3 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}-\frac {2 \left (31 a^{3}+48 a \,b^{2}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 d}-\frac {2 \left (7 a^{3}+6 a \,b^{2}\right ) \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {3 b \left (8 a^{2}+b^{2}\right ) x}{128}+\frac {21 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32}+\frac {21 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}+\frac {105 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64}+\frac {21 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}+\frac {21 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32}+\frac {3 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}+\frac {3 b \left (8 a^{2}+b^{2}\right ) x \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{128}+\frac {b \left (328 a^{2}-23 b^{2}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}+\frac {b \left (104 a^{2}+333 b^{2}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}-\frac {14 a^{3}+12 a \,b^{2}}{35 d}-\frac {10 a^{3} \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {3 b \left (8 a^{2}+b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{64 d}-\frac {2 \left (3 a^{3}+6 a \,b^{2}\right ) \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {2 \left (21 a^{3}+48 a \,b^{2}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{35 d}-\frac {2 \left (13 a^{3}-6 a \,b^{2}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 d}-\frac {2 a^{3} \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{8}}\) | \(636\) |
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Time = 0.31 (sec) , antiderivative size = 136, normalized size of antiderivative = 0.70 \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {1920 \, a b^{2} \cos \left (d x + c\right )^{7} - 896 \, {\left (a^{3} + 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{5} + 105 \, {\left (8 \, a^{2} b + b^{3}\right )} d x + 35 \, {\left (16 \, b^{3} \cos \left (d x + c\right )^{7} - 8 \, {\left (8 \, a^{2} b + 3 \, b^{3}\right )} \cos \left (d x + c\right )^{5} + 2 \, {\left (8 \, a^{2} b + b^{3}\right )} \cos \left (d x + c\right )^{3} + 3 \, {\left (8 \, a^{2} b + b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{4480 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 456 vs. \(2 (177) = 354\).
Time = 0.69 (sec) , antiderivative size = 456, normalized size of antiderivative = 2.35 \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=\begin {cases} - \frac {a^{3} \cos ^{5}{\left (c + d x \right )}}{5 d} + \frac {3 a^{2} b x \sin ^{6}{\left (c + d x \right )}}{16} + \frac {9 a^{2} b x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac {9 a^{2} b x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{16} + \frac {3 a^{2} b x \cos ^{6}{\left (c + d x \right )}}{16} + \frac {3 a^{2} b \sin ^{5}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{16 d} + \frac {a^{2} b \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{2 d} - \frac {3 a^{2} b \sin {\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{16 d} - \frac {3 a b^{2} \sin ^{2}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac {6 a b^{2} \cos ^{7}{\left (c + d x \right )}}{35 d} + \frac {3 b^{3} x \sin ^{8}{\left (c + d x \right )}}{128} + \frac {3 b^{3} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{32} + \frac {9 b^{3} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{64} + \frac {3 b^{3} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{32} + \frac {3 b^{3} x \cos ^{8}{\left (c + d x \right )}}{128} + \frac {3 b^{3} \sin ^{7}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{128 d} + \frac {11 b^{3} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{128 d} - \frac {11 b^{3} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{128 d} - \frac {3 b^{3} \sin {\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} & \text {for}\: d \neq 0 \\x \left (a + b \sin {\left (c \right )}\right )^{3} \sin {\left (c \right )} \cos ^{4}{\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.60 \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=-\frac {7168 \, a^{3} \cos \left (d x + c\right )^{5} - 560 \, {\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 12 \, d x + 12 \, c - 3 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} b - 3072 \, {\left (5 \, \cos \left (d x + c\right )^{7} - 7 \, \cos \left (d x + c\right )^{5}\right )} a b^{2} - 35 \, {\left (24 \, d x + 24 \, c + \sin \left (8 \, d x + 8 \, c\right ) - 8 \, \sin \left (4 \, d x + 4 \, c\right )\right )} b^{3}}{35840 \, d} \]
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Time = 0.43 (sec) , antiderivative size = 184, normalized size of antiderivative = 0.95 \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {3 \, a b^{2} \cos \left (7 \, d x + 7 \, c\right )}{448 \, d} + \frac {b^{3} \sin \left (8 \, d x + 8 \, c\right )}{1024 \, d} - \frac {a^{2} b \sin \left (6 \, d x + 6 \, c\right )}{64 \, d} + \frac {3 \, a^{2} b \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} + \frac {3}{128} \, {\left (8 \, a^{2} b + b^{3}\right )} x - \frac {{\left (4 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (5 \, d x + 5 \, c\right )}{320 \, d} - \frac {{\left (4 \, a^{3} + 3 \, a b^{2}\right )} \cos \left (3 \, d x + 3 \, c\right )}{64 \, d} - \frac {{\left (8 \, a^{3} + 9 \, a b^{2}\right )} \cos \left (d x + c\right )}{64 \, d} - \frac {{\left (6 \, a^{2} b + b^{3}\right )} \sin \left (4 \, d x + 4 \, c\right )}{128 \, d} \]
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Time = 11.80 (sec) , antiderivative size = 552, normalized size of antiderivative = 2.85 \[ \int \cos ^4(c+d x) \sin (c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {3\,b\,\mathrm {atan}\left (\frac {3\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (8\,a^2+b^2\right )}{64\,\left (\frac {3\,a^2\,b}{8}+\frac {3\,b^3}{64}\right )}\right )\,\left (8\,a^2+b^2\right )}{64\,d}-\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {3\,a^2\,b}{8}+\frac {3\,b^3}{64}\right )+10\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+2\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}+\frac {12\,a\,b^2}{35}+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}\,\left (6\,a^3+12\,a\,b^2\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\left (14\,a^3+12\,a\,b^2\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {12\,a\,b^2}{5}-\frac {26\,a^3}{5}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {6\,a^3}{5}+\frac {96\,a\,b^2}{35}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (\frac {62\,a^3}{5}+\frac {96\,a\,b^2}{5}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{15}\,\left (\frac {3\,a^2\,b}{8}+\frac {3\,b^3}{64}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {41\,a^2\,b}{8}-\frac {23\,b^3}{64}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}\,\left (\frac {41\,a^2\,b}{8}-\frac {23\,b^3}{64}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (\frac {13\,a^2\,b}{8}+\frac {333\,b^3}{64}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}\,\left (\frac {13\,a^2\,b}{8}+\frac {333\,b^3}{64}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\,\left (\frac {31\,a^2\,b}{8}+\frac {671\,b^3}{64}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9\,\left (\frac {31\,a^2\,b}{8}+\frac {671\,b^3}{64}\right )+\frac {2\,a^3}{5}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{16}+8\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}+28\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+56\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+70\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+56\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+28\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+8\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}-\frac {3\,b\,\left (8\,a^2+b^2\right )\,\left (\mathrm {atan}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )-\frac {d\,x}{2}\right )}{64\,d} \]
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